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LTC3602 Folha de dados(PDF) 19 Page - Linear Technology |
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LTC3602 Folha de dados(HTML) 19 Page - Linear Technology |
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19 / 28 page ![]() LTC3633A-2/LTC3633A-3 19 3633a23f APPLICATIONS INFORMATION Efficiency Considerations The percent efficiency of a switching regulator is equal to the output power divided by the input power times 100%. It is often useful to analyze individual losses to determine what is limiting the efficiency and which change would produce the most improvement. Percent efficiency can be expressed as: % Efficiency = 100% – (L1 + L2 + L3 +…) where L1, L2, etc. are the individual losses as a percent- age of input power. Although all dissipative elements in the circuit produce losses, three main sources usually account for most of the losses in LTC3633A-2 circuits: 1) I2R losses, 2) switching losses and quiescent power loss 3) transition losses and other losses. 1. I2R losses are calculated from the DC resistances of the internal switches, RSW, and external inductor, RL. In con- tinuous mode, the average output current flows through inductor L but is “chopped” between the internal top and bottompowerMOSFETs.Thus,theseriesresistancelook- ing into the SW pin is a function of both top and bottom MOSFET RDS(ON) and the duty cycle (DC) as follows: RSW = (RDS(ON)TOP)(DC) + (RDS(ON)BOT)(1 – DC) The RDS(ON)forboththetopandbottomMOSFETscanbe obtained from the Typical Performance Characteristics curves. Thus to obtain I2R losses: I2R losses = IOUT2(RSW + RL) 2. The internal LDO draws power from the SVIN input to regulate the INTVCC rail. The total power loss here is the sum of the switching losses and quiescent current losses from the control circuitry. Each time a power MOSFET gate is switched from low to high to low again, a packet of charge dQ moves from VIN to ground. The resulting dQ/dt is a current out of INTVCC that is typically much larger than the DC control bias current. In continuous mode, IGATECHG = f(QT + QB), where QT and QB are the gate charges of the internal top and bottom power MOSFETs and f is the switching frequency. For estimation purposes, (QT + QB) on each LTC3633A-2 regulator channel is approximately 2.3nC. To calculate the total power loss from the LDO load, simply add the gate charge current and quiescent cur- rent and multiply by the voltage applied to SVIN: PLDO = (IGATECHG + IQ) • SVIN 3. Other “hidden” losses such as transition loss, cop- per trace resistances, and internal load currents can account for additional efficiency degradations in the overall power system. Transition loss arises from the brief amount of time the top power MOSFET spends in the saturated region during switch node transitions. The LTC3633A-2 internal power devices switch quickly enough that these losses are not significant compared to other sources. Other losses, including diode conduction losses during dead-time and inductor core losses, generally account for less than 2% total additional loss. Thermal Considerations The LTC3633A-2 requires the exposed package backplane metal (PGND) to be well soldered to the PC board to provide good thermal contact. This gives the QFN and TSSOP packages exceptional thermal properties, which are necessary to prevent excessive self-heating of the part in normal operation. In a majority of applications, the LTC3633A-2 does not dissipate much heat due to its high efficiency and low thermal resistance of its exposed-back QFN package. However, in applications where the LTC3633A-2 is running at high ambient temperature, high input supply voltage, high switching frequency, and maximum output current load, the heat dissipated may exceed the maximum junc- tion temperature of the part. If the junction temperature reaches approximately 150°C, both power switches will be turned off until temperature returns to 140°C. To prevent the LTC3633A-2 from exceeding the maximum junction temperature of 125°C, the user will need to do some thermal analysis. The goal of the thermal analysis is to determine whether the power dissipated exceeds the maximum junction temperature of the part. The tempera- ture rise is given by: TRISE = PD • θJA |
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