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TS4985 Folha de dados(PDF) 23 Page - STMicroelectronics

Nome de Peças TS4985
Descrição Electrónicos  2x1.2w Stereo Audio Power Amplifier with Dedicated Standby Pins
PDF  29 Pages
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Fabricante Electrônico  STMICROELECTRONICS [STMicroelectronics]
Página de início  http://www.st.com
Logo STMICROELECTRONICS - STMicroelectronics

TS4985 Folha de dados(HTML) 23 Page - STMicroelectronics

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TS4985
Application Information
23/29
By following previous rules, the TS4985 can reach near zero pop and click even with high gains
such as 20dB.
Example calculation:
With
Rin =22kΩ and a 20Hz, -3db low cut-off frequency, Cin = 361nF. So, Cin =390nF with
standard value which gives a lower cut-off frequency equal to 18.5Hz. In this case,
(
Rin +2kΩ)x Cin = 9.36ms. When referring to the previous graph, if Cb =1µF and Vcc =5V, we
read 20ms max. This value is twice as high as our current value, thus we can state that pop and
click will be reduced to its lowest value. Minimizing both
Cin and the gain benefits both the pop
phenomena, and the cost and size of the application.
4.9
Dedicated standby control
TS4985 has two standby control inputs to allow to put each channel in standby mode
independently. In case a channel is active and another one in standby mode It’s very important
to be in line with a following recommendation to reach near zero pop. When left (right) channel
is active and right (left) channel is in standby mode it's necessary to put active channel in
standby mode first and then immediately (with regard to Standby time) activate right (left)
channel or both channels together in at the same moment.
4.10
Application example: differential-input BTL power stereo
amplifier
The schematic in
Figure 65 shows how to design the TS4985 to work in differential-input mode.
For this discussion, only the left-channel amplifier will be referred to.
Let:
R1R =R2L =R1, R2R =R2L =R2
CinR = CinL =Cin
The gain of the amplifier is:
Figure 65.
τin max. versus bypass capacitor
12
34
0
40
80
120
160
Vcc=5V
Vcc=3.3V
Vcc=2.6V
Tamb=25
°C
Bypass Capacitor Cb ( F)
Gvdif = 2
R2
R1
-------
×



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